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8x^2+122x=0
a = 8; b = 122; c = 0;
Δ = b2-4ac
Δ = 1222-4·8·0
Δ = 14884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14884}=122$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(122)-122}{2*8}=\frac{-244}{16} =-15+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(122)+122}{2*8}=\frac{0}{16} =0 $
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